Two dice are thrown simultaneously 500 times. Each time the sum of numbers
appearing on their top is noted and recorded as given in the following table.
Sum 2 3 4 5 6 7 8 9 10 11 12
Frequency 14 30 42 55 72 75 70 53 46 28 15
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Answered by
4
Answer:
(i) P (getting a sum more than 10) = P (getting a sum of 11) + P (getting a sum of 12)
= 28/500 + 15/500 = 28 + 15/500 = 43/500 = 0.869 = 0.09
(ii) P (getting a sum less than or equal to 5) = P (getting a sum of 5) +P (getting a sum of 4)+ P (getting a sum of 3) + P (getting a sum of 2)
= 55/500 + 42/500 + 30/500 + 14/500 = 141/500 = 0.282
(iii) P (getting a sum between 8 and 12 ) = P (getting a sum of 9) + P (getting a sum of 10) + P (getting a sum of 11)
= 53/500 + 46/500 + 28/500 = 127/500 = 0.254
Answered by
2
Answer:
do I have a chance for a second time and then I have to get to the next 5th and again and
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