Two dice are thrown simultaneously and the sum of numbers appearing on them is noted. Fimd the probability that sum is (i) 7 (ii) 9.
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Step-by-step explanation:
Total number of outcomes = n = 36
Let A be the event that sum on the dice is 7.
=> (4,3) (3,4) (5,2) (2,5) (6,1) (1,6)
= m = 6
P(A) = m/n = 6/36 = 1/6
Let B be the event that sum on the dice is 9.
=> (6,3) (3,6) (4,5) (5,4)
= m = 4
P(B) = m/n = 4/36 = 1/9
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