two dice are thrown simultaneously at random.find Probabilitiy of getting a sum of eight
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Answered by
1
Answer:
P(e)= sum of observations/no of samples
possibilities=
n(e)={(2,6),(3,5),(4,4),(5,3),(6,2)}=5
n(s)= {(1,1),(1,2),(1,3),(1,4)
........
(6,4),(6,5),(6,6)}=36
P(e)=5/36
(Probability must be represented in fraction and not in decimals.)
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Answered by
0
Answer:
5/36
Step-by-step explanation:
(2,6);(3,5);(4,4);(5,3);(6,2)
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