Question

two dice are thrown simultaneously find the probability of sum is less than 5​

Answer 1

Answer:

the following is possible outcomes

total outcomes are 36

there are only 6 outcomes which sum is less than 5

p(sum less than 5)=6/36

=1/6

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Answer 2

The probability of sum is less than 5​ is $\frac{1}{6}$.

Step-by-step explanation:

Given : Two dice are thrown simultaneously.

To find : The probability of sum is less than 5​ ?

Solution :

When two dice are thrown,

(1,1) (1,2) (1,3) (1,4) (1,5) (1,6)

(2,1) (2,2) (2,3) (2,4) (2,5) (2,6)

(3,1) (3,2) (3,3) (3,4) (3,5) (3,6)

(4,1) (4,2) (4,3) (4,4) (4,5) (4,6)

(5,1) (5,2) (5,3) (5,4) (5,5) (5,6)

(6,1) (6,2) (6,3) (6,4) (6,5) (6,6)

The favorable outcome is getting sum less than 5 i.e. {(1,1),(1,2),(1,3),(2,1),(2,2),(3,1)}= 6

Total number of outcome = 36

The probability of sum is less than 5 is given by,

$\text{Probability}=\frac{\text{Favorable outcome}}{\text{Total outcome}}$

$\text{Probability}=\frac{6}{36}$

$\text{Probability}=\frac{1}{6}$

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