Question

two dice are thrown simultaneously. find the probability of getting a doublet, sum as a even number, the sum divisible by 5​

Answer 1

Answer:

2 possibilities            ;             6 and 4           ,         5 and 5

Step-by-step explanation:

Answer 2

Step-by-step explanation:

two dice , so n(s) = 6² = 36

a) p.of.getting doublet

A = {(1,1), (2,2), (3,3), (4,4), (5,5), (6,6)}

n(A) = 6

p(A) = n(A) / n(s)

p(A) = 6/36 = 1/6

b) p.of.getting sum as even

A = {(1,1), (1,3), (1,5), (2,2), (2,4), (2,6), (3,1), (3,3), (3,5), (4,2), (4,4), (4,6), (5,1), (5,3), (5,5), (6,2), (6,4) , (6,6)}

n(A) = 18

p(A) = 18 / 36 = 1/2

c) p.of. sum divisible by 5

A = { (1,4) (2,3) (3,2) (4,1) (4,6) (5,5) (6,4) }

n(A) = 7

p(A) = 7/ 36