two dice are thrown simultaneously find the probability of getting a multiple of 5 as a product of numbers
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Answer:
total no. of outcomes =36
multiple of 5=5,10,15,20,25,30,33
total no. of possible outcomes =7
p(e)=no.of favourable outcomes /total no.of outcomes
7/36 answer
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Total possibility= 36
Product divisible by 5=11
11/36=0.31aprox.
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