Question

Two dice are thrown simultaneously find the probability of getting a multiple of 3 as a product of numbers

Answer 1

Answer:

in 1 dice=(1 2 3 4 5 6)

multiple of 3=3 and 6

so in 1 dice probability to get Multiple of 3 is 2

so In 2 dice Probability =2×2=4

So

favourable condition n(E)=4

sample space N(s)=12

Probability n(P)=n(E)/n(s)=4/12=1/3

therefore probability=1/3

I hope that it would be helpful to you brother