Question

Two dice are thrown simultaneously. Find the probability of getting a sum less than 4

Answer 1

There are 6 numbers in a dice

There are 2 dice so there are 12 numbers

Every number is coming 2 times

There are 3 numbers which are less than 4 so 3+3 =6 that means there are 6 numbers less than 4

Probability of getting less than 4 =

Total numbers = 12

Number less than 4 in 1 dice = 3

Number of dice =2

Number less than 4 in 2 dice = 6

6/12 = 3/6 = 1/2

Hope this will help you...

Answer 2

Step-by-step explanation:

QUESTION:

Two dice are thrown simultaneously. Find the probability of getting a sum less than 4.

SOLUTION

Total number of outcomes = 36

{ (1,1) ; (1,2) ; (1,3) ; (1,4) ; (1,5) ; (1,6)

(2,1) ; (2,2) ; (2,3) ; (2,4) ; (2,5) ; (2,6)

(3,1) ; (3,2) ; (3,3) ; (3,4) ; (3,5) ; (3,6)

(4,1) ; (4,2) ; (4,3) ; (4,4) ; (4,5) ; (4,6)

(5,1) ; (5,2) ; (5,3) ; (5,4) ; (5,5) ; (5,6)

(6,1) ; (6,2) ; (6,3) ; (6,4) ; (6,5) ; (6,6) }

Number of outcomes which has a sum less than 4 = 6

{ (1,1) ; (1,2) ; (1,3) ; (2,1) ; (2,2) ; (3,1) }

P ( getting the sum less than 4 ) = $\frac{6}{36} \\ = \frac{1}{6}$