Question

two dice are thrown simultaneously find the probability of getting a sum more than 7

Answer 1

Total out come will be 36.

Probablity of getting sum more than 7 is 15/36



Let me clear...possible with possible outcomes.

sum of 4 = (1,3), (2,2) ,(3,1)

sum of 5 = (1,4) , (3,2) , (2,3) , (4,1)

sum of 6 = (1 ,5) ,( 2,4) ,(3,3) ,(5,1) ,(4,2)

sum of 7 = (1,6) , (2,5) , (6,4) , (4,3) , (6,1), (5,2)

sum of 8 = (2, 6), (5,3), (4,4) ,(6,2) ,(3,5)

sum of 9 =(3,6), (4,5) ,(6,3) ,(5,4)

sum of 10 = (4,6) ,(5,5) ,(6,4)

sum of 11 = (5,6) ,(6,5)

sum of 12 = (6,6)


As u can count ...after sum of 7.



HOPE HELPS.......

Answer 2

Answer:

1(0)      2(1)    3(2)    4(3)    5(4)    6(5)  = 15 forms who is greater than 7

so 15/36  =  5/12 ans.

Step-by-step explanation:

here we start to 1 and other to sum who is greater than 7

similarly 2, 3, 4, 5, 6.