Question

Two dice are thrown simultaneously. find the probability of a. Getting a sum less than 6. b. Getting a doublet like (1, 1) (2, 2) (3, 3).

Answer 1

b.6 times
probability =6÷36
=1÷6
a.11÷36
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Answer 2

Total outcomes when two dives are thrown simultaneously = 36

a. P(A) = P(A) /P(S)
= 11/36
P(A) = 0.30555556

b. P(B) = 6/36
= 1/6