Question

Two dice are thrown simultaneously find the probability that the sum of the number appearing on the dice is six​

Answer 1

That's a total of 26 outcomes (two-dice rolls) that sum 6 or greater. The entire sample space, or the total number of possible roll outcomes, is 36. Therefore, the probability of rolling 6 or greater with two dice is the number of favorable outcomes (26) divided by the total number of outcomes (36): 26/36, or 13/18.

Answer 2

Answer:

The probability that the sum of the number appearing on the dice is six​ = $\frac{5}{36}$

Step-by-step explanation:

Given,

Two dice are thrown simultaneously.

To find,

The probability that the sum of the number appearing on the dice is six

Recall the formula:

The probability of occurring an event = $\frac{No \ of \ favourable \ outcomes}{Toal \ number \ of \ outcomes}$

Solution:

When two dice are thrown,

The outcomes are  = {(1,1),(1,2),(1,3)(1,4),(1,5),(1,6),(2,1),(2,2),(2,3)(2,4),(2,5),(2,6)(3,1),(3,2),(3,3)(3,4),(3,5),(3,6),(4,1),(4,2),(4,3)(4,4),(4,5),(4,6),(5,1),(5,2),(5,3)(5,4),(5,5),(5,6)(6,1),(6,2),(6,3)(6,4),(6,5),(6,6)}

Hence, the Total number of outcomes = 36

Favourable outcomes = outcomes with sum 6

= {(1,5),(2,4),(3,3),(4,2),(5,1)}

No of favourable outcomes = 5

Hence, Probability = $\frac{No \ of \ favourable \ outcomes}{Toal \ number \ of \ outcomes}$ = $\frac{5}{36}$

∴The probability that the sum of the number appearing on the dice is six​ = $\frac{5}{36}$

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