Question

Two dice are thrown simultaneously. The probability of an even number on one and a multiple of 3 on the other is
Option - (a) 1/6 (b) 5/12 (c) 5/6 (d) 11/36

Answer 1

Hello dear friend ,
by figuring out u can find the favorable outcomes ---2,3 ;  2,6 ; 4,3 ; 4,6 ; 6,3 ; 6;6

The answer to your question is : option .(a) 1/6

Hope this helps !! thankyou & goodluck!!

Answer 2

The probability of even number on one and multiple of 3 on other is $\bold{\frac{1}{6}}$

Solution:

Two dices are thrown simultaneously now the probability to get one dice as even and another as multiple of 3.

Now the total even number in a dice is 2, 4, 6 i.e. 3

The total number of multiples of 3 is 3, 6.

So the total combination or the sample space is $6 \times 6=36$  

The possibility of getting even and multiple of 3 are the following possibilities such as {(2,3) (2,6) (4,3)  (4,6) (6,3) (6,6)} =6  

The probability of getting even and multiple of 3,

= $\bold{\frac{\text { Possibility of getting even and multiple of } 3}{\text { total combination or the sample space }}=\frac{6}{36}= \frac{1}{6}}$