Question

two dice are thrown simultaneously what is the probability of getting a double or total of 4​

Answer 1

Answer:

Step-by-step explanation:

If 2dice are thrown sample space is 36

Number of S =36

Let A be the event which denotes doubles (1,1),(2,2),(3,3),(4,4),(5,5),(6,6)

Number of A =6

P(A)=n(A)/n(s)= 6/36=1/6

Let B be the event of getting total 4

(1,3),(2,2),(3,1)

Number of B= 3

P(B)=n(B)/n(s)=3/36=1/12

Probability of getting both sum as 4and also a double=P(A∩B)=1/36

So,probability of getting a double or a total of 4 is calculated using addition theorem of probability

P(A∪B)=P(A)+P(B)-P(A∩B)

=1/6+1/12-1/36

= 8/36=2/9