Question

Two dice are thrown simuntaneosly. find the probability of getting the sum as a odd number

Answer 1

If 2 dice are thrown simultaneously, wkt we have 6 ways in each die. If in 2, 6x6=36 ways. Therefore 1/2 of 36 = 18 odd and 18 even numbers.


Probability of getting odd = 18/36 = 1/2. Probability = 1/2

Answer 2

Answer: P(getting sum as odd number) = 1/2

Concept: Probability of a event to occur is given by

                P(event)=n(event)/n(Sample space)

                n(event) = number of favourable outcomes

                n(Sample space) = number of possible outcomes

Given: Two dice are thrown simultaneously and we have to find the probability of getting sum as a odd number.

To find: The probability of getting the sum as a odd number

Step-by-step explanation:

When 2 dice are rolled total possible outcomes are 36. They are :-

(1,1), (1,2), (1,3), (1,4), (1,5), (1,6)

(2,1), (2,2), (2,3), (2,4), (2,5), (2,6)

(3,1), (3,2), (3,3), (3,4), (3,5), (3,6)

(4,1), (4,2), (4,3), (4,4), (4,5), (4,6)

(5,1), (5,2), (5,3), (5,4), (5,5), (5,6)

(6,1), (6,2), (6,3), (6,4), (6,5), (6,6)

n(Sample Space) = 36

Let B be the event of getting sum as odd number

Hence the favourable outcomes are

B ={ (1,2),  (1,4), (1,6),

(2,1), (2,3),  (2,5),

(3,2), (3,4),  (3,6),

(4,1),  (4,3),  (4,5),

(5,2), (5,4), (5,6),

(6,1), (6,3), (6,5)}

n(B) = 18

Probability of a event to occur is given by

P(event)=n(event)/n(Sample)

P(B) = 18/36

P(B) = 1/2 or 0.5

Answer: When two dice are thrown simultaneously, the probability of getting the sum as a odd number is 1/2.

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