Math, asked by Madiha3343, 8 months ago


Two dice are thrown together and the score is recorded.
i) What is the probability of getting a total of 7?
ii) What is probability of getting product as 12?​

Answers

Answered by vikas2004
8

Answer:

(i) 1/6  (ii) 1/8

Step-by-step explanation:

SAMPLE SPACE = { (1,1),(1,2),(1,3),(1,4),(1,5),(1,6)

                                (2,1),(2,2),(2,3),(2,4),(2,5),(2,6)

                                (3,1),(3,2),(3,3),(3,4),(3,5),(3,6)

                                (4,1),(4,2),(4,3),(4,4),(4,5),(4,6)

                                (5,1),(5,2),(5,3),(5,4),(5,5),(5,6)

                                (6,1),(6,2),(6,3),(6,4),(6,5),(6,6) }

[i] P (getting a total of 7) = 6 / 36

                                           = 1 /6

SAMPLE SPACE = { (1,1),(1,2),(1,3),(1,4),(1,5),(1,6)

                                (2,1),(2,2),(2,3),(2,4),(2,5),(2,6)

                                (3,1),(3,2),(3,3),(3,4),(3,5),(3,6)

                                (4,1),(4,2),(4,3),(4,4),(4,5),(4,6)

                                (5,1),(5,2),(5,3),(5,4),(5,5),(5,6)

                                (6,1),(6,2),(6,3),(6,4),(6,5),(6,6) }

[ii] P (getting a product as 12 ) = 4 / 36

                                                    = 1 / 8

Answered by Anonymous
26

》AnSWeR:

(i) 1/6 (ii) 1/8

》Step-by-step explanation:

SAMPLE SPACE = { (1,1),(1,2),(1,3),(1,4),(1,5),(1,6)

(2,1),(2,2),(2,3),(2,4),(2,5),(2,6)

(3,1),(3,2),(3,3),(3,4),(3,5),(3,6)

(4,1),(4,2),(4,3),(4,4),(4,5),(4,6)

(5,1),(5,2),(5,3),(5,4),(5,5),(5,6)

(6,1),(6,2),(6,3),(6,4),(6,5),(6,6) }

[i] P (getting a total of 7) = 6 / 36

= 1 /6

SAMPLE SPACE = { (1,1),(1,2),(1,3),(1,4),(1,5),(1,6)

(2,1),(2,2),(2,3),(2,4),(2,5),(2,6)

(3,1),(3,2),(3,3),(3,4),(3,5),(3,6)

(4,1),(4,2),(4,3),(4,4),(4,5),(4,6)

(5,1),(5,2),(5,3),(5,4),(5,5),(5,6)

(6,1),(6,2),(6,3),(6,4),(6,5),(6,6) }

[ii] P (getting a product as 12 ) = 4 / 36

= 1 / 8

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