Question

Two dice are thrown together. What is the probability that the numbers obtained on one of the dice is multiple of number obtained on the other dice?

Answer 1

If two dice are thrown together , the total number of outcomes = 36

The favorable outcomes for the number obtained on one of the dice is multiple of number obtained on the other dice :

(1,1) (2,1) (3,1) (4,1) (5,1) (6,1)

(2,2) (4,2) (6,2)

(3,3) , (4,4) , (5,5) (6,3) (6,6)

Number of favorable outcomes = 11

Now , the probability that the number obtained on one of the dice is multiple of number obtained on the other dice

$= \dfrac{\text{No. of favorable outcomes}}{\text{Total outcomes}}$

$\dfrac{14}{36}=\dfrac{7}{18}$

Hence, the probability that the number obtained on one of the dice is multiple of number obtained on the other dice is

$\dfrac{7}{18} .$