Question

Two dice are tossed simultaneously. Find the probability of getting
(i) an even number on both dice.
(ii) the sum of two numbers more than 9.​

Answer 1

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Probability of an event = Number of outcomes favourable to that event/ Number of all possible outcomes.

The set of all possible outcomes is called the sample space and is denoted by S.

When two dice are tossed, the possible outcomes are (1,1),(1,2),(1,3),(1,4),(1,5),(1,6), (2,1),(2,2),(2,3),(2,4),(2,5),(2,6),(3,1),(3,2),(3,3),(3,4),(3,5),(3,6),(4,1),(4,2),(4,3),(4,4),(4,5),(4,6),(5,1),(5,2),(5,3),(5,4),(5,5),(5,6),(6,1),(6,2),(6,3),(6,4),(6,5),(6,6). Hence n(S) = 36.

But we want the desired event E that the number should be same on both dice. Such outcomes (1,1),(2,2),(3,3)(4,4),(5,5) and (6,6). We have 6 desired outcomes. So n(E) = 6

Hence the probability of getting same number. on both dice = n(E)/ n(S) = 6/36 = 1/6

Answer 2

Answer:

1) 9/36 = 1/4

2) 18/36= 1/2