Question

two dice are tossed together. find the probability of getting a doublet or a sum of 10

Answer 1

Total outcomes - 6x6 = 36 
Doublets = (1,1) (2,2) (3,3) (4,4) (5,5) (6,6) = 6 outcomes

Probablity - 
6/36 = 1/6

Sum of Ten = (4,6) (6,4) (5,5)  = 3 outcomes 
3/36 = 1/12

Answer 2

Given:

Two dice

To find:

The probability of getting a double

The probability of getting a sum of 10

Solution:

Sample space = ( 1, 0 ), ( 1, 1 ), ( 1, 2 )... ( 6, 6 )

Hence,  

Sample space = 36

To find the probability of getting a doublet,

Outcomes = ( 1, 1 ), ( 2, 2 ).. ( 6, 6 )

Possible outcomes = 6

P (getting a double) = 6 / 36  

Hence, P (getting a double) = 1 / 6

To find the probability of getting a sum of 10,

Possible outcomes = ( 4, 6 ), ( 6, 4 ), ( 5, 5 )  

P (getting a sum of 10 ) =3/36

Hence, P ( getting a sum of 10 ) = 1 / 12

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