two dice each bearing number 1to6 are rolled together find the probability that the sum of the number on the uppermost faces of the two dice is
4or5
7,8,or9
between 5and8
more than 10
less than 6
Answers
Answer:
Total number of possible outcomes on rolling two dice together = 36
(i) To get the sum of numbers 4 or 5 favourable outcomes are: (1, 3) ,(3, 1) , (2,2), (1, 4) , (4, 1), (2, 3) and (3,2).
Number of favourable outcomes = 7
Probability (P) =number of favourable outcomes / total number of possible outcomes
P (getting a sum 4 or 5) = 7/36
(ii) To get the sum of numbers 7,8,9 favourable outcomes are: (1, 6) ,(6, 1) , (2,5), (5, 2) , (3, 4), (4, 3) , (2,6) , (6, 2) ,(3,5) , (5,3), (4, 4) , (3, 6),(6,3),(4,5), (5,4)
Number of favourable outcomes = 15
Probability (P) =number of favourable outcomes / total number of possible outcomes
P (getting a sum 7,8 or 9) = 15/36
(iii) To get the sum of numbers between 5 & 8 i.e getting sum of 6 or 7 , favourable outcomes are: (1, 5) ,(5, 1) , (2,4), (4, 2) , (3, 3), (1, 6) , (6,1) , (2, 5) ,(5,2) , (3,4), (4, 3).
Number of favourable outcomes = 11
Probability (P) =number of favourable outcomes / total number of possible outcomes
P (getting a sum between 5 & 8) = 11/36.
(iv) To get the sum of numbers more than 10 i.e getting sum of 11 or 12 , favourable outcomes are: (5, 6) ,(6, 5) , (6,6)
Number of favourable outcomes = 3
Probability (P) =number of favourable outcomes / total number of possible outcomes
P (getting a sum more than 10) = 3 /36 = 1/12
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