Question

two dices are thrown simultaneously find the probability number of the sum of two numbers appearing on the top is more than equal to 10

Answer 1

p(sum of two numbers appearing on the top is more than equal to 10)=no.of favourable outcomes/Total no . of possible outcomes
=3/36
=1/12

Answer 2

ftotal outcomes 36
(1,1)(1,2)(1,3)(1,4)(1,5)(1,6)
(2,1)(2,2)(2,3)(2,4)(2,5)(2,6)
(3,1)(3,2)(3,3)(3,4)(3,5)(3,6)
(4,1)(4,2)(4,3)(4,4)(4,5)(4,6)
(5,1)(5,2)(5,3)(5,4)(5,5)(5,6)
(6,1)(6,2)(6,3)(6,4)(6,5)(6,6)
probability getting sum more tan 10 = 6/36 =1/6