Math, asked by mgsivavishnu2002, 11 months ago

Two die are thrown simultaneously.what is the probability that the Sum of numbers appearing on the dices is (i) 7 (ii) greater than 5 (iii)1​

Answers

Answered by agamdeep34
1

Answer:

(1) 7

1to6

probability/total outcome

6/7

greater than5

probability=6

total outcome6

probability/total outcome

6/6=1

3) 1

probability1

outcome6

1/6

Answered by junaidkhan61
0

Step-by-step explanation:

(i) chances of sum of digit is 7= (3,4),(4,3),(5,2),(2,5),(6,1) and (1,6)

no. of possible outcomes = 6

total no. of outcomes = 6×6=36

probability=6/36

=1/6

(ii) chances of the sum of digit > 5=(1,5),(5,1),(1,6),(6,1),(2,4),(4,2),(2,5),(5,2),(2,6),(6,2),(3,3),(3,4),(4,3),(3,5),(5,3),(3,6),(6,3),(4,5),(5,4),(4,6),(6,4),(5,6),(6,5) and (6,6)

no. of possible outcomes= 24

total no. of outcomes = 6×6=36

probability= 24/36=2/3

(iii) chances of sum of digit is 1= nothing

probability= 0/36=0

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