Two dies are throughn once find the probablity of getting an even no. On first dieor a total of 6
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The two dies can get numbers from 1 to 6 (both inclusive)on them. So, the total number of possibilities are 6*6=36.
The score (sum of the numbers on two dies) can be from 2 to 12.
The given problem requires those cases in which the score is not divisible either by 3 or 4. So, the sum can be 2, 5, 7, 10, 11.
This is possible in 1+4+6+3+2=16 ways.
Hence, the required probability is 16/36=4/9.
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