Two different dice are rolled simultaneously. Find the probability that the sum of the numbers appearing on the two dice is 10.
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1/12 is the answer.........
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Sum Of Observation = 36[(1,1),(1,2),(1,3),(1,4),(1,5),(1,6)
(2,1),(2,2),(2,3),(2,4),(2,5),(2,6)
(3,1),(3,2),(3,3),(3,4),(3,5),(3,6)
(4,1),(4,2),(4,3),(4,4),(4,5),(4,6)
(5,1),(5,2),(5,3),(5,4),(5,5),(5,6)
(6,1),(6,2),(6,3),(6,4),(6,5),(6,6)]
Favourable Observation = 3[(4,6),(5,4),(6,4)]
Probability = Favourable Obs / No . of Obs
P(of getting Numbers Whose Sum = 10) = 3/36
P(of getting Numbers Whose Sum = 10) = 1/12
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(2,1),(2,2),(2,3),(2,4),(2,5),(2,6)
(3,1),(3,2),(3,3),(3,4),(3,5),(3,6)
(4,1),(4,2),(4,3),(4,4),(4,5),(4,6)
(5,1),(5,2),(5,3),(5,4),(5,5),(5,6)
(6,1),(6,2),(6,3),(6,4),(6,5),(6,6)]
Favourable Observation = 3[(4,6),(5,4),(6,4)]
Probability = Favourable Obs / No . of Obs
P(of getting Numbers Whose Sum = 10) = 3/36
P(of getting Numbers Whose Sum = 10) = 1/12
Hope U Understood
Mark This Brainliest If This Helped You
Thankx
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