Math, asked by Aizakhan234, 1 year ago

Two different dice are thrown together. Find the probability that the numbers obtained have
(I) even sum
(Ii) even product

Answers

Answered by nikki1231
13
Total no. of outcomes = 6² = 36

1) probability = 18/36 = 3/6 { (1,1) (1,3) (1,5) (2,2)

(2,4) (2,6) (3,1) (3,3) (3,5) (4,2) (4,4) (4,6) (5,1) (5,3)

(5,5) (6,2) (6,4) (6,6) }

2) probability = 27/36 = 9/12 { (1,2) (1,4) (1,6) (2,1)

(2,2) (2,3) (2,4) (2,5) (2,6) (3,2) (3,4) (3,6) (4,1)

(4,2) (4,3) (4,4) (4,5) (4,6) (5,2) (5,4) (5,6)

(6,1) (6,2) (6,3) (6,4) (6,5) (6,6) }

HOPE U UNDERSTAND

PLS MARK IT AS BRAINLIEST

Aizakhan234: But the no. Of favourable outcomes In 2nd part is 28
nikki1231: sry
nikki1231: i also typed 5,5
nikki1231: soo
nikki1231: (5,5)
nikki1231: pls mark it as brainliest
Aizakhan234: Then what will be the answer of 2nd part
Aizakhan234: Is it 7/6..??
Answered by samridhisrivas2205
1

Answer:

1- 1/2

2- 3/4

Step-by-step explanation:

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