Two different dice are thrown together. Find the probability that the numbers obtained have
(I) even sum
(Ii) even product
Answers
Answered by
13
Total no. of outcomes = 6² = 36
1) probability = 18/36 = 3/6 { (1,1) (1,3) (1,5) (2,2)
(2,4) (2,6) (3,1) (3,3) (3,5) (4,2) (4,4) (4,6) (5,1) (5,3)
(5,5) (6,2) (6,4) (6,6) }
2) probability = 27/36 = 9/12 { (1,2) (1,4) (1,6) (2,1)
(2,2) (2,3) (2,4) (2,5) (2,6) (3,2) (3,4) (3,6) (4,1)
(4,2) (4,3) (4,4) (4,5) (4,6) (5,2) (5,4) (5,6)
(6,1) (6,2) (6,3) (6,4) (6,5) (6,6) }
HOPE U UNDERSTAND
PLS MARK IT AS BRAINLIEST
1) probability = 18/36 = 3/6 { (1,1) (1,3) (1,5) (2,2)
(2,4) (2,6) (3,1) (3,3) (3,5) (4,2) (4,4) (4,6) (5,1) (5,3)
(5,5) (6,2) (6,4) (6,6) }
2) probability = 27/36 = 9/12 { (1,2) (1,4) (1,6) (2,1)
(2,2) (2,3) (2,4) (2,5) (2,6) (3,2) (3,4) (3,6) (4,1)
(4,2) (4,3) (4,4) (4,5) (4,6) (5,2) (5,4) (5,6)
(6,1) (6,2) (6,3) (6,4) (6,5) (6,6) }
HOPE U UNDERSTAND
PLS MARK IT AS BRAINLIEST
Aizakhan234:
But the no. Of favourable outcomes In 2nd part is 28
Answered by
1
Answer:
1- 1/2
2- 3/4
Step-by-step explanation:
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