Question

Two different dice are thrown together. Find the probability that the numbers obtained have
I.even sum
Ii.even product

Answer 1

I. even sum= 2,4,6,8,10,12
no of favourable outcomes
(1,1), (1,3),(3,1),(2,2),(1,5),(5,1),(4,2),(2,4),(3,3),(4,4),(5,3),(3,5),(6,2),(2,6),(5,5),(6,4),(4,6),(6,6)

prb = 18/36 = 1/2

ii. even product = 2,4,6,8,10,12,16,18,

no of fav outcomes
(1,2),(2,1),(2,2),(4,1),(1,4),(6,1),(1,6),(2,3),(3,2),(4,2),(2,4),(5,2),(2,5),(6,2),(2,6),(4,4),(6,3),(3,6)

prb = 18/36 = 1/2