Question

Two different dice are thrown together. Find the probability that the
product of the numbers appeared is less than 18.

Answer 1

Solution :-

If two different dice are thrown together, they have numbers 1, 2, 3, 4, 5 and 6 and 1, 2, 3, 4, 5 and 6 on them.

Total number of outcomes -

(1, 1) ; (1, 2) ; (1, 3) ; (1, 4) ; (1, 5) ; (1, 6) ; (2, 1) ; (2. 2) ; (2, 3) ; (2, 4) ; (2, 5) ; (2, 6) ; (3, 1) ; (3, 2) ; (3, 3) ; (3, 4) ; (3, 5) ; (3, 6); (4, 1) ; (4, 2) ; (4, 3) ; (4, 4) ; (4, 5) ; (4, 6) ; (5, 1) ; (5, 2) ; (5, 3) ; (5, 4) ; (5, 5) ; (5, 6) ; (6, 1); (6, 2) ; (6, 3) ; (6, 4) ; (6, 5) ; (6, 6) = 36

The probability that the product of the numbers appeared is less than 18

= (1, 1) ; (1, 2) ; (1, 3) ; (1, 4) ; (1, 5) ; (1, 6) ; (2, 1) ; (2, 2) ; (2, 3) ; (2, 4) ; (2, 5) ; (2, 6) ; (3, 1) ; (3, 2) ; (3, 3) ; (3, 4) ; (3, 5) ; (4, 1) ; (4, 2) ; (4, 3) ; (4, 4) ;  (5, 1) ; (5, 2) ; (5, 3) ; (6, 1) ; (6, 2)

= 26/36

= 13/18

Answer.

Answer 2

Answer:

The probability that product of the numbers appeared is less than 18

= (1, 1) ; (1, 2) ; (1, 3) ; (1, 4) ; (1, 5) ; (1, 6) ; (2, 1) ; (2, 2) ; (2, 3) ; (2, 4) ; (2, 5) ; (2, 6) ; (3, 1) ; (3, 2) ; (3, 3) ; (3, 4) ; (3, 5) ; (4, 1) ; (4, 2) ; (4, 3) ; (4, 4) ;  (5, 1) ; (5, 2) ; (5, 3) ; (6, 1) ; (6, 2)

= 26/36

= 13/18