Two different dice are thrown together. What is the probability of getting a total of 6 or 7 of the numbers on two dice?
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Answer:
5/36 and 1/6
Step-by-step explanation:
S = { (1,1) , (1,2) , (1,3) , (1,4) , (1,5) , (1,6) ,
(2,1) , (2,2) , (2,3) , (2,4) , (2,5) , (2,6) ,
(3,1) , (3,2) , (3,3) , (3,4) , (3,5) , (3,6) ,
(4,1) , (4,2) , (4,3) , (4,4) , (4,5) , (4,6) ,
(5,1) , (5,2) , (5,3) , (5,4) , (5,5) , (5,6) ,
(6,1) , (6,2) , (6,3) , (6,4) , (6,5) , (6,6) }
n(S) = 36
The probability of getting a total of 6 be 'A'
A = { (3,3) , (4,2) , (2,4) , (5,1) , (1,5) }
n(A) = 5
P(A) = 5/36
The probability of getting a total of 7 be 'B'
B = { (6,1) , (1,6) , (5,2) , (2,5) , (4,3) , (3,4) }
n(B) = 6
P(B) = 6/36
= 1/6
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