Question

two different dice are tossed together.find the probability of getting doublet.and probability of getting sum 10,of numbers on the two dice.

Answer 1

As double dies are thrown therefore the total outcomes become 36.The outcomes are as following
(1,1),(1,2),(1,3),(1,4),(1,5),(1,6)
(2,1),(2,2),(2,3),(2,4),(2,5),(2,6)
(3,1),(3,2),(3,3),(3,4),(3,5),(3,6)
(4,1),(4,2),(4,3),(4,4),(4,5),(4,6)
(5,1),(5,2),(5,3),(5,4),(5,5),(5,6)
(6,1),(6,2),(6,3),(6,4),(6,5),(6,6).
1) Now to have a doublet we should found same numbers between brackets such as (1,1),(2,2),(3,3),(4,4),(5,5),(6,6)
Therefore the favourable cases are 6
Probability =

2)We should count outcomes having sum of 10 such that (4,6),(5,5)(6,4).So favourable outcomes are 3
Probability =

Hope this would have been clear to you buddy. Please mark as the brainliest.

Answer 2

Hello friend your answer is
The probability of getting doublet is
Total outcomes =36
and doublet =6
then P=6/36=1/6
2.
The probability of getting the sum of 10 is =3/36
1/12