Question

Two different dice are tossed together. Find the probability :
(1) of getting doublet.
(2) of getting a sum of 10, of the numbers on the two dice.​

Answer 1

Answer:

(1) 6

(2)4+6,6+4

Step-by-step explanation:

If we add 4+6 we gat answer 10,and we had find sum of 10from 1to6

Answer 2

✬ P(D) = 1/6 ✬

✬ P(S) = 1/12 ✬

Step-by-step explanation:

Given:

• Two different dice are tossed together.

To Find:

• Probability of getting a doublet ?
• Probability of getting a sum of 10, of the numbers on the two dice.

Solution: Total outcomes which will come after tossing two different dice :- 36

[ Outcomes are ➘ ]

• (1,1) (1,2) (1,3) (1,4) (1,5) (1,6)

• (2,1) (2,2) (2,3) (2,4) (2,5) (2,6)

• (3,1) (3,2) (3,3) (3,4) (3,5) (3,6)

• (4,1) (4,2) (4,3) (4,4) (4,5) (4,6)

• (5,1) (5,2) (5,3) (5,4) (5,5) (5,6)

• (6,1) (6,2) (6,3) (6,4) (6,5) (6,6)

( 1 ) Doublets (D) are

• (1,1) , (2,2) (3,3) (4,4) (5,5) (6,6)

∴ Favourable outcomes of D = 6

➟ P(D) = Favourable outcomes/Total outcomes

$\implies{\rm }$ P(D) = 6/36

$\implies{\rm }$ 1/6

So , probability of getting a doublet is 1/6.

______________________

( 2 ) Getting a sum (S) of 10

• (4,6) (5,5) (6,4)

∴ Favourable outcomes of S = 3

➟ P(S) = Favourable outcomes/Total outcomes

$\implies{\rm }$ P(S) = 3/36

$\implies{\rm }$ 1/12

Hence, probability of getting a sum of 10 is 1/12.