two different dice are tossed together find the probility ..(1)of getting a double.(2) of getting a sum 10,of the number on the two dice.
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1)6/36. = 1/6
2) 3/36 = 1/ 12
double means (2,2)( 3,3)( 4,4) (5,5 )(6,6 )
2) 3/36 = 1/ 12
double means (2,2)( 3,3)( 4,4) (5,5 )(6,6 )
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Given:
Two dice
To find:
The probability of getting a double
The probability of getting a sum of 10
Solution:
Sample space = ( 1, 0 ), ( 1, 1 ), ( 1, 2 )... ( 6, 6 )
Hence,
Sample space = 36
To find the probability of getting a doublet,
Outcomes = ( 1, 1 ), ( 2, 2 ).. ( 6, 6 )
Possible outcomes = 6
P (getting a double) = 6 / 36
Hence, P (getting a double) = 1 / 6
To find the probability of getting a sum of 10,
Possible outcomes = ( 4, 6 ), ( 6, 4 ), ( 5, 5 )
P (getting a sum of 10 ) =3/36
Hence, P ( getting a sum of 10 ) = 1 / 12
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