Two different numbers, when divided by 47, leave remainders 13 and 23
respectively.If their sum is divided by the same number 47, what will be the
remainder?
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Answer:
36
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let we multiply 47 into 1 times =47×1=47
then first number will be 47+13=60 and second number be 47+23=70
now according to question we add both numbers 60 and 70vrespectively , we get 130 and divide by 47 it means 130/47 = 47×2+36
so. required remainder will be 36 ans
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