Question

Two digit numbers are formed from the digits 9, 7,5,3, 2 where the digits are not repeated. Find the probability of the events.

1) The number is even.​

Answer 1

Step-by-step explanation:

possible two digit no are 97,95,93,92,79,75,73,72,59,57,53,52,39,37,35,32,29,27,25,23

n(s) =20

even no are=92,72,52,32

n(e) =4

probablity of no being even=n(e) /n(s)

=4/20

=1/5

Answer 2

Answer:

The probability of the two digit number being even is  $\frac{1}{5}$

Step-by-step explanation:

Given digits are: 9, 7, 5, 3, 2

Two digit numbers are to be formed without repetition.

We have to find the probability of the number being even.

We know that probability =  $\frac{No.ofFavorable outcomes}{TotalNo.of outcomes}$

Favorable outcomes = 92, 72, 52, 32

Total outcomes = 97, 95, 93, 92, 79, 75, 73, 72, 59, 57, 53, 52, 39, 37, 35, 32, 29, 27, 25, 23.

Therefore, number of favorable outcomes = 4

Therefore, number of total outcomes = 20

Therefore, required probability = $\frac{4}{20}$

                                                    = $\frac{1}{5}$

Therefore, the probability of the two digit number being even is  $\frac{1}{5}$