Two eggs are drawn successively with replacement from a lot containing 10% defective eggs. Find the probability that there is at least one defective egg.
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Answer:
Your answer is 0.19
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Step-by-step explanation:
P( at least one defective )
= 1 - P( neither egg drawn is defective )
= 1 - P( first egg drawn is not defective ) × P( second egg is not defective )
= 1 - 0.9 × 0.9
= 1 - 0.81
= 0.19
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