Question

Two electric bulbs A and B are marked 22V,40W and 220V,60W respectively. Which one has greater resistance?

Answer 1

Answer:

written below-

Explanation:

As electric power in relation to voltage andresistance is given as P=V^{2}/R where, V isvoltage, R is resistance, and P is the power.So, for a constant voltage, power is `So, for a constant voltage, power is inverselyrelated to the resistance. Thus, the powerof 40 W will have the larger resistance andthat s because the resistance prevents theflow of current at a constant voltage, so ifthere is less resistance only then there will bemore electric power.`

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Answer 2

Answer:

Bulb A has greater resistance

Explanation:

$v_{1} = 220V , p_{1} = 40W$$v_{2} = 220V , p_{2} = 60W$

$p_{1} = v^{2}_{1} / r_{1}$                 $p_{2} = v^{2}_{2} / r_{2}$

$r_{1} = v^{2}_{1} / p_{1}$                 $r_{2} = v^{2}_{2} / p_{2}$

$r_{1} = 1210$ ω              $r_{2} = 806.67$ω