two electric bulbs have resistances in the ratio 1:x.they are joined in series.the resistance of thicker wire is 10Ω .the total resistance of combination will be
A)40Ω
B)40/3Ω
C)5/2Ω
D)100Ω
i am new to this topic .plz explain in detail from basics....
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D is the answer
Its easy
Just concentrate on the ratio
Its 1 to x
1 is to 10
Then to make it 1 we need 10:100
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