Question

Two electric bulbs having resistances in the ratio 2:3 are connected in parallel to a voltage sources of 220V. the ratio of power dissipated between them is what?​

Answer 1

Answer:

Given R₁ : R₂ = 2 : 3

Power dissipated in parallel combination is given by

P = V²/R

P₁ = V²/R₁

P₂ = V²/R₂

P₁ : P₂ = V²/R₁ : V²/R₂ = R₂ : R₁

∴ P₁ : P₂ = 3 : 2