Question

Two electric bulbs p and q have their resistances in the ratio of

Answer 1

As we know p=V*I.

Now coming to series circuit current constant so P=V^2/R. So if R more in series power dissipation is less and low R having high power dissipation . Invers relationship.

Coming to parallel circuit voltage constan so we can write P=IR*I (as V=I*R)

That means P=I^2R.

So it shows if R is more power dissipation is more and low R low will be the power dissipation. In parallel circuit.

So, ratio of power dissipation will be R2/R1= 2/1

Hope I clear you