Chemistry, asked by rty12346, 1 year ago

two electric bulbs pnq have the resistance in the ratio 1 ratio to they are connected in series across a battery find the ratio of their power dissipation in these bulb

Answers

Answered by harshith7799

1

P = vi
p = i^r
p = i^(2r)

note: as resistors are in series and ratio is 1 r1 = r2
Req = 2r

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