Question

two electric bulbs rated 100 watts;220 volt and 60 watt ;220 volt are connected in parallel to an electric mains of 220 volts find the current drawn by the bulbs from the mains

Answer 1

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Answer 2

Answer:

Required current 0.73 A

Explanation:

Given parameters,

Potential difference (V)=220 V

Power of lamp 1

$p_1=100 \: W$

Powet of lamp 2

$P_2=60 \: \: W$

Both the bulbs are connected in parallel, Therefore, the potential difference across each of them will be 220 V,because no division of voltage occurs in parallel circuit.

For first lamp,

$R_1= \frac{ {220}^{2} }{100}$

For the second lamp,

$R_2= \frac{ {220}^{2} }{60}$

When they are connected in parallel line,

$\frac{1}{R} = \frac{1}{R_1} + \frac{1}{</p><p>R_2}$

$= \frac{1}{ \frac{ {220}^{2} }{100} } + \frac{1}{ \frac{ {220}^{2} }{60} }$

$R = \frac{ {220}^{2} }{160}$

By Ohm's law,

$V = IR$

$220 = \frac{ {220}^{2} }{160} I$

Therefore I= 0.73 A