Question

Two electrons separated by distance r experience a force f between them . the force between a proton and a singly ionized helium atom separated by distance 2r is
1)4F
2)2F
3)F/2
4)F/3​

Answer 1

Answer:

Explanation:

Force between electron and proton is F=kq²/r²

The force between a singly ionised hileum atom and proton is :-

Singly ionised helium atom have 2 proton and 1 electron......... 1 electron and 1 proton cancel the force leaving 1 proton(+ve charge)

The force between 1 proton from helium and 1 proton is....

F'=kq²/(2r)²

F'=kq²/4r²

F'=kq²/4r²

¯¯¯¯¯¯¯¯¯¯¯¯

F=kq²/r²

F'=4F

Answer 2

Answer:

F/4

Explanation:

e1-------------e2

distance is "r".

p---------------he

distance is "2r".

F1 = $\frac{1}{4\pi ε0 }$ *  $\frac{Q1Q2}{r^{2} }$

F1 = F

F2 = $\frac{1}{4\piε0 }$ * $\frac{Q1Q2}{2r^{2} }$

F2 = $\frac{1}{4\piε0 }$ * $\frac{Q1Q2}{4r^{2} }$

F2 = $\frac{1}{4\piε0 }$ *  $\frac{Q^{2} }{4r^{2} }$

F2 = F/4

F1/F2 = F/4

hence F/4 is the answer.