Question

Two elements, X (Atomic mass 16) and Y (Atomic mass 14) combine to form compounds A, B and C. The ratio of different masses of Y which combine with fixed mass of X in A, B and C is 1:3:5. If 32 parts by mass of X combine with 84 parts by mass of Y in B, then in C, 16 parts by mass of X will combine with _______.
(A) 14 parts by mass of Y
(B) 42 parts by mass of Y
(C) 70 parts by mass of Y
(D) 82 parts by mass of Y

Answer 1

Answer:

c) 70 parts by mass of Y

Explanation:

Number of elements = 2 = X and Y

Number of compounds = 3 = A B and C

In B, 32 parts of X combine with Y = 84 parts

16 parts of X combine with Y =  42 parts

The number of parts of X in both B and C is of equal to the masses of Y combining with a fixed mass of X in B and C in ratio 3:5

Mass of Y in B / Mass of y in C

=3/5

= 42 parts / Mass Y in C = 3/5

Mass of Y in C

= 5/3×42

=70 parts

Thus, parts by mass of X will combine with 70 parts by mass of Y

Answer 2

Answer:

Explanation:

Hope it helps....!!!