Two engines pass each other moving in opposite directions with uniform speed of 30 m/s. One of them is blowing a whistle of frequency 540 hz. Calculate the frequency heard by driver of second engine before they pass each other. Speed of sound is 330 m/sec:
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Answer:
f=[C−Vo/C+Vs]×fo
where
f : Observed frequency, fo : source frequency
c : speed of sound
Vo : velocity of the receiver relative to the medium (positive if the receiver is moving towards the source)
Vs : velocity of the source relative to the medium (positive if the source is moving away from the receiver)
f = [(330+30)/(330-30)]×540
= 648 Hz
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