Accountancy, asked by satyamgupta9234, 10 months ago

Two persons ajay and vijay started working for a company in similar jobs on january, 1, 1991. Ajay's initial monthly salary was rs.400, which increases by rs.40 after every year. Vijay's initial monthly salary was rs.500 which increases by rs.20 after every six months. If these arrangements continue till december, 31, 2000, find the total salary they received during that period.

Answers

Answered by basavaraj5392
0

Answer:

getting 93,300

salary of X = 300*12+330*12+360*12........600*12

=> 12(300+330+360.....600)

=> a=300 , d=30 , n=10

=> 52,200

salary of Y = 200*6+215*6......

=> 6(200+215+230.....upto 20 terms)

=> a=200 , d=15 , n=20

=> 41,100

total = 93,300

Answered by Sinthushaa
0

Answer:

Ajay

Monthly salary = ₹ 400

total salary for 10 year = 400×12×10

= 48000

Increment every year of ₹40

Total increment for 10 years = 400

Total salary received by Ajay = 48,400

Vijay

Monthly salary = ₹ 500

Total salary for 10 year = 500×12×10

= 60000

increment every year = 20+20= 40

total increment for 10 years = 400

Total salary received by Vijay = 60,400

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