Question

two equal charged identical metal spheres a and b repel each other with force 'f'. the spheres are kept fixed with a distance 'r' between them. a third identical , but uncharged sphere c is brought in contact with a and then placed at the mid - point of the line joining a and b. the magnitude of the net electric force on c is

Answer 1

I hope it will be helpful to you

Answer 2

Answer:

$F_{\text {net }}=F$

Explanation:

$F_{2}=\frac{K\left(\frac{Q}{2}\right)^{2}}{\left(\frac{r}{2}\right)^{2}} \quad F_{1}=\frac{K(Q)\left(\frac{Q}{2}\right)}{\left(\frac{r}{2}\right)^{2}}$

$F_{\text {net }}=F_{1}-F_{2}=\frac{2 K Q^{2}}{r}-\frac{K Q^{2}}{r^{2}}=\frac{K Q^{2}}{r^{2}}$

$F_{\text {net }}=F$

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