Question

two equal charges of identical spheres are placed at point A and B . Third identical sphere C is touched with B and placed at mid point of A and B .if forces between A and B in initial condition is f .find bet force of C​

Answer 1

Answer:

i think the answer is F

Explanation:

when c will touch b then charges will get distributed between them equally that is q/2

so,force by A on c will be 2kq^2/x^2 and force due to B will be kq^2/x^2 . Fa >Fb hence on subtracting Fa from Fb the answer will be F