Question

Two equal charges placed in air and separated by distance 2m repel each other with the force of 10^24 kgwt . Calculate the magnitude of either of the charge

Answer 1

Answer:

Explanation:

F = k q² / r ²

here F = 10²⁴ kgwt

       k = 9.0 x 10⁹ n/m²

       r = 2

9.0 x 10⁹ x q² / 4 = 10²⁴

∴ 9.0 x 10⁹ x q² = 4 x 10²⁴  

∴  q² = 4 x 10²⁴  / (9.0 x 10⁹ )

∴  q² =  04.44 x 10 ¹⁴

∴  q = 6.67 x 10⁷

So the magnitude of the charge = 6.67 x 10⁷ C

Answer 2

As per column’s law :The magnitude of  force between two charged particles is given by the equation ;F=k×(q1)(q2)/r*2.

Putting the value of  k'sof value 9×10*9 we can calculate the charge and 1gf=0.0098N=0.001.

Coulom’slaw :

The law states  that like charges repel each other  and opposite charges attract each other , with a force magnitude of which  proportional to the product of the charges and inversely proportional to the square of the distance between them.