Question

Two equal charges placed in air separated by a distance of
1.5 m repel each other with a force of 2 x 10^4 kg f. Calculate the magnitude
of either of the charges.

Answer 1

Answer:

Let each charge be q . Using Coulomb's Law, F = 14piε0 q^2r^2 Here, r = 2 m F = 10^-4 × 9.8 N = 10^-4 × 10 N q^2 = F × 4piε 0 × r^2 = 10^-4 × 10