Question

two equal cubes are placed at jointly in a row find the ratio of the total surface area of the new cuboid to that the sum of the surface areas of two cubes​

Answer 1

Answer:

Step-by-step explanation:

Let the side be of length"a"cm of both cubes

S.A of both cubes=6a^2 each

So, the dimensions of new cuboid will be,

l=2a cm.

b=a cm.

h=a cm.

T.S.A=2(2a^2+a^2+2a^2)

=2×5a^2

=10a^2..............(1)

Sum of S.A. of smaller cubes=12a^2........(2)

(1)/(2)

=5:6