Question

two equal cubes with side 6 CM are placed one above the other forming a cuboid find the total surface area of the cuboid thus form

Answer 1

Answer:

$360 \mathrm{~cm}^2$

Step-by-step explanation:

Step 1: Add the areas of each of the six rectangular sides of a cuboid to determine its surface area. The cuboid's length, width, and height can also be labelled, and the surface area (SA) can be calculated using the formula SA=2lw+2lh+2hw.

Step 2: From Everett's Many Worlds Interpretation of quantum physics, one may view the sixth dimension. It describes the sixth dimension as the "phase space" of the collection of parallel universes emerging from the special beginning conditions of our universe.

Step 3: Side of the cube, $a=6 \mathrm{~cm}$

Therefore, Length of the cuboid, $I=6 \mathrm{~cm}$

Breadth of the cuboid, $b=6 \mathrm{~cm}$

And height, $\mathrm{h}=6+6=12 \mathrm{~cm}$

Total surface area $=2(\mathrm{lb}+\mathrm{lh}+\mathrm{bh})$

$=2(6 \times 6+6 \times 12+6 \times 12)$

$=360 \mathrm{~cm}^2$

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Answer 2

The total surface area of the cuboid formed by placing two equal cubes with sides 6 cm above the other is 360 cm².

A cuboid with the dimensions 6 cm (width), 6 cm (length), and 12 cm is created when two equal cubes with sides of 6 cm are stacked on top of one another (height).

The cuboid's total surface area can be calculated by adding the areas of each of its six faces.

Each of the bottom and top faces measures 6 cm x 6 cm = 36 cm² each.

The surface area of the front and back faces is 6 cm x 12 cm = 72 cm² each.

Additionally, the left and right faces each have an area of 6 cm x 12 cm = 72 cm² each.

As a result, the cuboid's overall surface area is:

= 2(36 cm²) + 2(72 cm²) + 2(72 cm²)

= 72 cm² + 144 cm² + 144 cm² = 360 cm².

Consequently, the cuboid formed by stacking two identical cubes with sides of 6 cm on top of one another has a 360 cm² total surface area.

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