Question

two equal like to equal and like charges repel each other with a force of 50 mg weight when they are 19 CM apart in here what is the magnitude of each charge​

Answer 1

Answer:

Hey there,

Charge of the object = q the separation is 5cm and 0.05 cm.

The given force is 0.144N which is repulsive in nature.

According to the law of Columbus, F = Kq²/r², 0.016 × (0.05)² × 10⁻⁹ = Q², Square rooting both the sides, q = 0.4 × 0.05 × 10⁻⁵.

This determines the magnitude of the charge to be 0.2μC

Thanks for asking.